How to Access and Rename Doubles that are Stored in a Large Cell

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Pat
Pat 2020-2-17
评论： Stephen23 2020-2-18
I have a Cell that is 1x193. Each of the 193 elements is a 500x100 double.
I need to be able to access every element in this cell and rename each double to be Data1, Data2, Data3, etc. such that I can perform means on the rows of Data1, Data2, etc.
Does anyone have suggestions for how to accomplish this?
  2 个评论
Stephen23
Stephen23 2020-2-17
"Does anyone have suggestions for how to accomplish this? "
Use indexing.
Creating/accessing numbered variables would be entirely the wrong way to go about this:
https://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval
Indexing is simple, neat, and very efficient. Using numbered variables is a sign that you are doing something wrong.
Pat
Pat 2020-2-18
I did come across that link while looking into this, but I didn't have a good workaround for it.
I understand what you are saying, but I don't really know what syntax I should use to do accomplish this...

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回答（1 个）

Bhaskar R
Bhaskar R 2020-2-17
You no need to rename every elecment(500x100 double) of the cell which leads much complications, you can perform your operation directly using command cellfun
result_mean = cellfun(@(x)mean(x, 2), cell_array, 'UniformOutput', false); % cell_array is your vartiable
You can access mean values of the data as
result_mean{1}, result_mean{2}..result_mean{193}; % for mean values of the each row of the double array
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Pat
Pat 2020-2-18
Okay.
So I need to convert my cell into a 3D array then?
dataStorage = cat(3, dataStore{:});
But, I still have to calculate the average of all of the first elements that were in my cells previously. Would that be something like:
rowAvg = squeeze(mean(dataStorage, 2));
or
rowAvg = mean(dataStorage,3)
Thanks for the help.
Stephen23
Stephen23 2020-2-18
Do NOT use datastore as a variable name, it is the name of an important inbuilt function.
Where C is your cell array, calculate the mean of each row:
A = cat(3, C{:});
M = mean(A,2)
It will have size 500x1x193. Use indexing to access particular pages, or permute or reshape to rearrange those dimensions. Avoid squeeze.

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