Plotting an infinite series with multiple variables.
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Hi, recently I solved PDE of a 1D wave equation and came to the solution of:
my question while vague,also comes from a place of genuine interest. How exactly would I plot this? I tried splitting it into various components and then summing those components into one function but it just plotted lines for me which leads me here. Any and all help is appreciated; I'm rather novice at this program so detailed explaninations are very welcomed in reference to why you chose particular path way to achieving something.
quick chicken scratch code:
%variables
x=(0:.2:1);
t=(0:.2:1);
n=(0:.4:2);
A = 0.02.*(-1.*(((2.*(n.^2)-5).*sin(n.*pi))/((n.^4)-5.*(n.^2)+4)));
B = 0.02.*(sin(n.*pi.*x).^2);
C = 0.02.*(cos(n.*pi.*t));
u = A.*B.*C;
fplot(u);
1 个评论
David Hill
2020-2-18
You could try something like:
[x,t]=meshgrid(0:.2:1,0:.2:1);
u=zeros(size(x));
for n=3:100
u=u-.02*(2*n^2-5)*sin(n*pi)/(n^4-5*n^2+4)*sin(n*pi*x).*cos(n*pi*t);
end
surf(x,t,u);
Your equation does not make much sense to me, since for n=1 and n=2 you are dividing by zero. How can n=0:.4:2 based on your equation?
采纳的回答
Raunak Gupta
2020-2-21
Hi,
David’s comment above provides a solution but has some missing terms. You may follow the bottom code for doing the same. Also as mentioned in comment n=1 and n=2, the value of u will be undefined so the summation should start at n=3. For the range of x and t you can change them in meshgrid below as per required.
% x and t ranges
xRange = 0:0.02:1;
tRange = 0:0.02:1;
[x,t] = meshgrid(xRange,tRange);
u = zeros(size(x));
for n=3:100
u = u - (0.02*(2*n^2-5)*sin(n*pi)/(n^4-5*n^2+4))*(sin(n*pi*x)^2).*cos(n*pi*t);
end
surf(x,t,u);
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