MATLAB Answers

Index in position 2 exceeds array bounds

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Fernanda Vanessa Almendarez Juarez
Answered: Hyeokjin Jho on 18 Feb 2020
I have a problem with this, I dont know whats wrong
n=4;
r= 0.012;
pos = [0 0; 0 0.5; 0.5 0.5; 0.5 0]
a = zeros(1,n)
i=1
while( i<=n)
for(j=1:1:n-1)
for(k=1:1:n-1)
x = pos(k+1,1)-pos(1,j) %%------> I have the problem here
It says "Index in position 2 exceeds array bounds"

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Answers (2)

KSSV
KSSV on 18 Feb 2020
You size of pos is 4x2....you are trying to accessing third coulmn from pos....where as it has only two columns..so obviously you will end up with error.

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Hyeokjin Jho
Hyeokjin Jho on 18 Feb 2020
Since n = 4, for(j=1:1:n-1) will make j from 1 to 3.
However pos is 4x2 matrix. When j is 3, pos(1,j) refers outside of the matrix boundary.

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