Yes, you can use a loop to calculate the hourly averages for 365 days using the find function. Here's an example code that should work:
for day = 1:365
% calculate the indices of the precipitation values for the current day
for hour = 1:24
% calculate the indices of the precipitation values for the current hour of the day
% calculate the hourly average
end
end
You can use nested loops so that you need not write code manually for 24*365 times. We can use a loop to iterate through all 365 days of the year. For each day, we use the find function to calculate the indices of the precipitation values for this day, and then another loop to iterate through all 24 hours of the day. For each hour, we again use the find function to calculate the indices of the precipitation values for this hour, and then calculate the hourly average using the mean function.
