You were close when using diff. You need to think what characterizes all four combinations. The code below should be what you need.
v=[1;1;0;0;0;1;0;1;0;1];
d=diff(v);
u=v(1:(end-1));%shrink by 1 to make it the same size as d
clc
%if [0;0]
%then diff==0, v==0
L= d==0 & u==0;
fprintf('[0 0]: %d\n',sum(L))
%if [0;1]
%then diff==-1
L= d==-1;
fprintf('[0 1]: %d\n',sum(L))
%if [1;0]
%then diff==1
L= d==1;
fprintf('[1 0]: %d\n',sum(L))
%if [1;1]
%then diff==0, v==1
L= d==0 & u==1;
fprintf('[1 1]: %d\n',sum(L))
