How could I code for loop with this values?

Question

Mohmmad Abu Yousuf 2020-2-21

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/506793-how-could-i-code-for-loop-with-this-values

评论： Mohmmad Abu Yousuf 2020-2-23

采纳的回答： darova

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Hi guys! I need a simple help from you.

I want to create a for loop with nested if-else condition. Afterthat I want to plot them. Could you guys help me please! I have written the pseudocode below. I need the coding based on this. Please help me out.

Thank you in advance.

%'A' consists some values (e.g. 40, 60, 30, 80, 70, 50, 90, 30);
for A % it will take first 2 values 
% 'B' is the maximum value consisting of 2 values from 'A' 
% e.g. max (40,60) = 60 then this 60 will be first value of A and last
% value will be 30 so max(60,30) is 60. Afterthat first value is 60 and 2nd value is 80 
% so, max(60,80) is 80 likewise. 
     B = max (A);
% then 'C' is the last value from 'A' which is taken to get the 'B', will be assigned to 'C'.    
   
    C = 60; % for 2nd itaration C = 30, for 3rd C = 80, for 4th C = 70, for 5th C = 50 and so on.. 
    % If C reduces 30% of B then,
        x = C/10
        fprintf ('This is your value %d',x );
    else
        fprintf ('This is not your value %d',x );
    end 
end
plot ('x' vs simulation time)

3 个评论
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madhan ravi 2020-2-21

Illustration of expected result would help.

Mohmmad Abu Yousuf 2020-2-22

Thank you,

Result would be like this. Could you please help me Sir.

for 1st iteration:

A is 40 and 60,

so, B is 60,

C is 60 then

if C reduces 30% of B

x = C/10

else

x = C/5

end

for 2nd iteration:

A is 60 and 30,

so, B is 60,

C is 30 then

if C reduces 30% of B

x = C/10

else

x = C/5

end

for 3rd iteration:

A is 60 and 80,

so, B is 80,

C is 80 then

if C reduces 30% of B

x = C/10

else

x = C/5

end

for 4th iteration:

A is 80 and 70,

so, B is 80,

C is 70 then

if C reduces 30% of B

x = C/10

else

x = C/5

end

this will go on till the last value of A

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Answer 1

darova 2020-2-22

2
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/506793-how-could-i-code-for-loop-with-this-values#answer_416839

编辑：darova 2020-2-23

在 MATLAB Online 中打开

This script should give you success you are looking for

A = [40, 60, 30, 80, 70, 50, 90, 30];
B = A(1);
for i = 2:length(A)
    B = max(B,A(i));
    C = A(i);
    if C/B < 0.7
        x = C/10;
    else
        x = C/5;
    end
end