How could I code for loop with this values?

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Mohmmad Abu Yousuf
Mohmmad Abu Yousuf 2020-2-21
评论： Mohmmad Abu Yousuf 2020-2-23
Hi guys! I need a simple help from you.
I want to create a for loop with nested if-else condition. Afterthat I want to plot them. Could you guys help me please! I have written the pseudocode below. I need the coding based on this. Please help me out.
Thank you in advance.
%'A' consists some values (e.g. 40, 60, 30, 80, 70, 50, 90, 30);
for A % it will take first 2 values
% 'B' is the maximum value consisting of 2 values from 'A'
% e.g. max (40,60) = 60 then this 60 will be first value of A and last
% value will be 30 so max(60,30) is 60. Afterthat first value is 60 and 2nd value is 80
% so, max(60,80) is 80 likewise.
B = max (A);
% then 'C' is the last value from 'A' which is taken to get the 'B', will be assigned to 'C'.
C = 60; % for 2nd itaration C = 30, for 3rd C = 80, for 4th C = 70, for 5th C = 50 and so on..
% If C reduces 30% of B then,
x = C/10
fprintf ('This is your value %d',x );
else
fprintf ('This is not your value %d',x );
end
end
plot ('x' vs simulation time)
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madhan ravi
madhan ravi 2020-2-21
Illustration of expected result would help.
Mohmmad Abu Yousuf
Mohmmad Abu Yousuf 2020-2-22
Thank you,
Result would be like this. Could you please help me Sir.
for 1st iteration:
A is 40 and 60,
so, B is 60,
C is 60 then
if C reduces 30% of B
x = C/10
else
x = C/5
end
for 2nd iteration:
A is 60 and 30,
so, B is 60,
C is 30 then
if C reduces 30% of B
x = C/10
else
x = C/5
end
for 3rd iteration:
A is 60 and 80,
so, B is 80,
C is 80 then
if C reduces 30% of B
x = C/10
else
x = C/5
end
for 4th iteration:
A is 80 and 70,
so, B is 80,
C is 70 then
if C reduces 30% of B
x = C/10
else
x = C/5
end
this will go on till the last value of A

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采纳的回答

darova
darova 2020-2-22
编辑：darova 2020-2-23
This script should give you success you are looking for
A = [40, 60, 30, 80, 70, 50, 90, 30];
B = A(1);
for i = 2:length(A)
B = max(B,A(i));
C = A(i);
if C/B < 0.7
x = C/10;
else
x = C/5;
end
end
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darova
darova 2020-2-23
Oh, understand. My bad. I corrected the code. See now

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