R2015a plot problem with ticklabel definition
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x = 0:0.01:20;
y1 = 200*exp(-0.05*x).*sin(x);
y2 = 0.8*exp(-0.5*x).*sin(10*x);
figure % new figure
[hAx,hLine1,hLine2] = plotyy(x,y1,x,y2);
title('Multiple Decay Rates')
xlabel('Time (\musec)')
ylabel(hAx(1),'Slow Decay') % left y-axis
set(hAx(1),'ytick',-200:50:200)
set(hAx(2),'ytick',linspace(-0.8,0.8,5),'YTickLabel',num2str(y2(:), '%0.1f'))
When I run this, I get only positive values for the y axis on the right and the values aren't correct. Any solution??
回答（2 个）
Walter Roberson
2020-2-21
编辑：Walter Roberson
2020-2-21
0 个投票
You only ask for 5 ticks in your linspace, with labels derived from y2 not from what you linspace. Your first 5 y2 values are all positive.
6 个评论
Angshuman Podder
2020-2-21
set(hAx(2),'YTickLabel',num2str(y2(:), '%0.2f'))
Still no luck!! The negative values aren't getting printed.
Walter Roberson
2020-2-22
No more tick labels will be output than you have defined for tick positions. You define the tick positions with linspace of length 5.
Your vector is long, 2001 elements. You do not want to create a tick label for each one of those.
Angshuman Podder
2020-2-22
Walter Roberson
2020-2-22
hAx(2).YRuler.TickLabelFormat = '%0.1f';
without setting the YTick or YTickLabel properties (unless the automatically generated values turn out not to be good enough.)
This requires R2014b or later.
Angshuman Podder
2020-2-24
Spencer Chen
2020-2-21
Well, you have set you ytick labels to:
num2str(y2(:), '%0.1f')
Maybe you meant?
num2str(linspace(-0.8,0.8,5), '%0.1f')
Blessings,
Spencer
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2020-2-21
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