Has to be postive integer or logical.
2 次查看(过去 30 天)
显示 更早的评论
Attempted to access t(0); index must be a positive integer or logical.
I'm trying to make it that as t is 0, the value is a given input "a". Here's my code:
function y = mynewton(f,a,n)
t(0)=a;
for i=[0:n]
t(i+1)=t(i-1)-f(t(i-1))/diff(f(x),t(i-1));
end
y=t;
采纳的回答
Wayne King
2012-10-13
编辑:Wayne King
2012-10-13
MATLAB indexes from 1, not 0 like C, so you must do
t(1) = a;
and then in your for loop, you cannot start from 1, because you attempt to access t(i-1) and f(i-1). Starting from i = 1, this would error.
Also, I'm not sure what you're trying to do with f(x). MATLAB will not understand what you mean by f(x), that is human notation for doing math.
It looks like you are trying to do numerical computation, not symbolic, in which case f will be a vector. You have to address elements of a vector by using meaningful indices from 1 to the length of the vector.
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Symbolic Math Toolbox 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!