Has to be postive integer or logical.
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Attempted to access t(0); index must be a positive integer or logical.
I'm trying to make it that as t is 0, the value is a given input "a". Here's my code:
function y = mynewton(f,a,n)
t(0)=a;
for i=[0:n]
t(i+1)=t(i-1)-f(t(i-1))/diff(f(x),t(i-1));
end
y=t;
1 个评论
per isakson
2012-10-13
Matlab indexing is one-based by design
采纳的回答
Wayne King
2012-10-13
编辑：Wayne King
2012-10-13
MATLAB indexes from 1, not 0 like C, so you must do
t(1) = a;
and then in your for loop, you cannot start from 1, because you attempt to access t(i-1) and f(i-1). Starting from i = 1, this would error.
Also, I'm not sure what you're trying to do with f(x). MATLAB will not understand what you mean by f(x), that is human notation for doing math.
It looks like you are trying to do numerical computation, not symbolic, in which case f will be a vector. You have to address elements of a vector by using meaningful indices from 1 to the length of the vector.
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