Error: Too many output arguments

Question

Barry Allen 2020-2-25

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/507393-error-too-many-output-arguments

编辑： Stephen23 2020-2-25

I have written a code for my final year project . I called a crn(). I get a error that too many arguments. but when I run the function code alone, I get the output with single argument.

function crn(tow)
Q =20;
Pi=[0.3,0.4,0.2,0.5,0.4];
Pa=10;
%tow=0.5
Pdbar=15;
Y=4;
fs=10000;
yi=[1,3,5,2,3];
y1=[1,2,5,8,7];
y2=10;
yj=[2,3,4,5,2];
N=5;
z=sum(Pi(2:N).*yi(2:N));
S=(Pa*y2)/(1+z);
alpha=sqrt((2*Y)+1)*Q^-1*Pdbar;
a=sum(Pi(2:N).*y1(2:N));
yj=yj(3:N);
yj=[yj 0];
b=sum(Pi(2:N).*yj);
bet=sum(log2((1+(sum(Pi(2:N).*yi(2:N))/(1+b)))))-(a/(1+a));
A = ((1-(Q*(alpha+(sqrt(tow*fs)*Y))))+((1-tow)*((Y*sqrt(fs))/(2*sqrt(2*3.14)))*tow^(-0.5)*exp(-(alpha+(sqrt(tow*fs)*Y))^2)/2));
B = (log2(1+((tow*S)/(1-tow)))+((1-tow)*(1-(Q*(alpha+(sqrt(tow*fs)*Y))))*(S/(((bet+1)*(1-tow))+(S*tow))*(1-tow))));
dR_tow=((A*B*10^(-7))/3);
%disp(dR_tow);
end

T=1;
tow_min=0;
tow_max=T;
while (tow_max-tow_min)>0.02
    tow_bar=(tow_max+tow_min)/2;
    a=crn(tow_bar);
    b=crn(tow_min);
    if a==b
        tow_min=tow_bar;
    else
        tow_max=tow_bar;
    end
end
tow0=tow_bar;
disp("tow0="+tow);

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Stephen23 2020-2-25

编辑：Stephen23 2020-2-25

"...but when I run the function code alone, I get the output with single argument."

Nope.

At the end of your function you use disp to display something, but the function does not return any output arguments:

https://www.mathworks.com/help/matlab/ref/function.html

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Answer 1

Subhadeep Koley 2020-2-25

1
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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/507393-error-too-many-output-arguments#answer_417232

在 MATLAB Online 中打开

Hi, this is because you function crn is not returning anything. If you want to return dR_tow then use the code below.

function dR_tow = crn(tow)
    Q =20;
    Pi=[0.3,0.4,0.2,0.5,0.4];
    Pa=10;
    %tow=0.5
    Pdbar=15;
    Y=4;
    fs=10000;
    yi=[1,3,5,2,3];
    y1=[1,2,5,8,7];
    y2=10;
    yj=[2,3,4,5,2];
    N=5;
    z=sum(Pi(2:N).*yi(2:N));
    S=(Pa*y2)/(1+z);
    alpha=sqrt((2*Y)+1)*Q^-1*Pdbar;
    a=sum(Pi(2:N).*y1(2:N));
    yj=yj(3:N);
    yj=[yj 0];
    b=sum(Pi(2:N).*yj);
    bet=sum(log2((1+(sum(Pi(2:N).*yi(2:N))/(1+b)))))-(a/(1+a));
    A = ((1-(Q*(alpha+(sqrt(tow*fs)*Y))))+((1-tow)*((Y*sqrt(fs))/(2*sqrt(2*3.14)))*tow^(-0.5)*exp(-(alpha+(sqrt(tow*fs)*Y))^2)/2));
    B = (log2(1+((tow*S)/(1-tow)))+((1-tow)*(1-(Q*(alpha+(sqrt(tow*fs)*Y))))*(S/(((bet+1)*(1-tow))+(S*tow))*(1-tow))));
    dR_tow=((A*B*10^(-7))/3);
end