Find/Match index of variable from an array

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Hi, I have this code which I am using to find index of variable a from an array b
a = 2;
b =[ 1 2 3 4 5 6 7 8 9 10];
for i = 1:1:size(b,2)
if (find (a == b))
[~,zq(i)] = (min(b(i)- a));
end
end
The problem is the result "zq", in which I am getting all ones, so I donot know the position, where a is being matched.
Does any one know?
  2 个评论
Alex Mcaulley
Alex Mcaulley 2020-2-26
You are obtaining all ones because "b(i)- a" is scalar and the minimum value of a scalar is allways itself.

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采纳的回答

Bhaskar R
Bhaskar R 2020-2-26
zq = find(b == a)

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