32Bit RGBA Image
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Hello,
i read via MicroMager Core succseedfull images in Graymode - But the device give me an 32bit RGBA Image that would not
display with function imshow()
import mmcorej.*
mmc = CMMCore;
mmc.unloadAllDevices();
mmc.loadSystemConfiguration ('C:\Program Files\Micro-Manager-2.0gamma\DijSDKcameraMgr.cfg');
mmc.prepareSequenceAcquisition('DijSDKcamera');
mmc.startContinuousSequenceAcquisition(0);
imgRaw = mmc.getLastImage(); %mmc.snapImage(); %img = mmc.getImage();
pixelType = 'uint8';%8BIT GRAY default
if depth == 4
pixelType = 'uint32';%32BIT RGBA can't display img as 32BIT RGBA only 16Bit RGB is possible ?
elseif depth == 2
pixelType = 'uint16';%16BIT RGB not supportet by Micromanger normaly 32bit or 8bit
end
img = typecast(imgRaw,pixelType);
img = reshape(img, [width, height]);
img = transpose(img);
cla reset;
imshow(img);
mmc.unloadAllDevices(); %complettly destruct MMCore
How i can convert tzhe image correctly ? The Funktion image(img) Display an point cloud of image, but not in real colors given from map...
thx for any suggestions
Karsten (www.FlexxVision.de)
4 个评论
Guillaume
2020-2-26
编辑:Guillaume
2020-2-26
Please answer Image Analyst question. We need to know the type of imgRaw that's returned by your device. Is it double, uint8 or something else? We also need to know the size. whos imgRaw will give us all that information.
Once we know that, we can probably figure out a way to display your image. It's probably trivial, just split the transparency channel from the colour channels.
Also, doesn't your library document the memory arrangement of the data returned by getLastImage? That would also be useful information for us to have.
采纳的回答
Guillaume
2020-2-26
"My Camera give me back an RGBA Image R8|G8|B8|A8 = 32 Bit"
"size is : width*height*(bpp/3)"
Shouldn't that be width*height*(bpp/4) ?
Assuming it's 4 bytes per pixel, and that imgRaw is indeed of class uint8:
img = permute(reshape(imgRaw, 4, width, height), [3, 2, 1])
imgRGB = img(:, :, 1:3); %discard alpha channel which is all 0
imshow(imgRGB);
This assumes that the image pixel are stored in row-major order, which your code also assumed.
16 个评论
Guillaume
2020-2-27
Oh! I made a typo. It should have been:
imgRGB = img(:, :, [3, 2, 1]); %was missing one :
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