Receiving error vectors must be the same length when trying to plot.
显示 更早的评论
I'm trying to model Earth's surface temperature with the radiative forcing of CO2 changing through time. For years 1600-1744 (i called them 1:144 interms of t in my code) [CO2]is constant, in 1745-1953 (145:358 interms of t in my code) [C02] is increasing by 0.068%/year, in 1954-2100 (359:500 in terms of t in my code) [CO2] is increasing by 0.4%. I have a function that I'm referencing which calculates the change in atmospheric emissivity redulting from the change in [CO2].
my function I'm referencing:
function e = eps_atm(CO2)
e = 0.8*(1+(0.0541*log(CO2/280)));
end
%% CO2 variation Climate Model %%
%set up constants
so = 1360; %units = W/m2
albedo = 0.3; %units = none
sigma = 5.67*10^-8; %units = W/((m^2)*(K^4))
p = 997; %units = kg/m^3
cw= 4181; %units = J/(kg*K)
h = 100; %units = m3
a = 0.0514; %units = none
co2 = 280; %units = none
deltat = 31556700; %units = seconds
nsteps = 500; %nsteps from i.c.
T(1) = 250; %units = K
for t = 1:nsteps
hold on;
if t == 1:144
T(t+1)= (((1+eps_atm(280)/2)*((so*(1-albedo))/4)-(sigma*T(t)^4))/(p*cw*h))*deltat+T(t);
elseif t == 145:358
T(t+1)= (((1+eps_atm(280*(1+0.00068*((t)-143)))/2)*((so*(1-albedo))/4)-(sigma*T(t)^4))/(p*cw*h))*deltat+T(t);
elseif t == 359:500
T(t+1)= (((1+eps_atm(280*(1+0.004*((t)-357)))/2)*((so*(1-albedo))/4)-(sigma*T(t)^4))/(p*cw*h))*deltat+T(t);
end
end
figure(1)
hold on;
time = [1:nsteps+1]*deltat;
plot(time/31556700, T,'x')
采纳的回答
更多回答(0 个)
类别
在 帮助中心 和 File Exchange 中查找有关 Map Display 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!