Replacing character between square brackets

2020 3 2
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更新时间：2020 3 2
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A={'[ABC; DEF];[GHI; JKH];'; '[ZBC; YEF];[XHI; UKH];'}
I need to replace ";" only which are appearing within sqare brackets with "^"

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Stephen23
Stephen23 2020-3-2
编辑：Stephen23 2020-3-2

0 个投票

>> A = {'[ABC; DEF];[GHI; JKH];'; '[ZBC; YEF];[XHI; UKH];'}
A =
'[ABC; DEF];[GHI; JKH];'
'[ZBC; YEF];[XHI; UKH];'
>> B = regexprep(A,'(\[[^\]]+);([^\]]+\])','$1^$2')
B =
'[ABC^ DEF];[GHI^ JKH];'
'[ZBC^ YEF];[XHI^ UKH];'
or perhaps:
>> B = regexprep(A,'(?<!\]);(?!\[)','^')
B =
'[ABC^ DEF];[GHI^ JKH];'
'[ZBC^ YEF];[XHI^ UKH];'

6 个评论
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What if we have more than one ";" in a cell
e.g
>> A = {'[ABC; DEF; LMN];[GHI; JKH; OPQ; RST];'; '[ZBC; YEF; UVW; XYY; DFF; TRR];[XHI; UKH];'}
Stephen23
Stephen23 2020-3-2
"What if we have more than one ";" in a cell"
Then you need to specify the expected output. I cannot guess what you want.
Muhammad Rahil Rafiq
编辑：Muhammad Rahil Rafiq 2020-3-2
My apologies.
Your earlier command is replacing only one last char ";".
I need to replace all ";" within square brackets
Stephen23
Stephen23 2020-3-2
>> A = {'[ABC; DEF; LMN];[GHI; JKH; OPQ; RST];'; '[ZBC; YEF; UVW; XYY; DFF; TRR];[XHI; UKH];'}
A =
'[ABC; DEF; LMN];[GHI; JKH; OPQ; RST];'
'[ZBC; YEF; UVW; XYY; DFF; TRR];[XHI; UKH];'
>> B = regexprep(A,'(\[[^\]]+\])','${strrep($1,'';'',''^'')}')
B =
'[ABC^ DEF^ LMN];[GHI^ JKH^ OPQ^ RST];'
'[ZBC^ YEF^ UVW^ XYY^ DFF^ TRR];[XHI^ UKH];'

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