Hi,
I think there was some typo in your question, you have said columns with same size and mentioned correctly in one case([Inf;Inf] and [1;1]), but you have mentioned {[2x6],[1,1],[Inf;inf]} incorrectly a row vector. Irrespective of that the sort function will return the values in the same order as the values were passed in if the size is the same. So I think you have to probably write some code to rearrange if there are elements of the same size and probably the following might be useful:
Basins = {ones(2,6),[Inf;Inf],[1;1],[Inf,Inf],[1,1]};
[sz,I] = sort(cellfun('size',Basins,2),'ascend');
Basins = Basins(I);% Basins = {{[Inf;Inf],[1;1],[Inf,Inf],[1,1],2x6 double}}
d = diff(sz);
l = (find(d == 0));%Finding the arrays of similar size
%Sorting them by mean if they have the same size
for i=1:1:length(l)
k = l(i);
C = Basins(k:k+1);
[~,J] = sort(cellfun(@mean,C),'ascend');% You can write your custom function here instead of mean
C = C(J);
Basins(k:k+1) = C;
end
%Basins = {{[1;1],[Inf;Inf],[1,1],[Inf,Inf],2x6 double}}
Hope this Helps!
