How to do this while loop

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Robin Li
Robin Li 2020-3-5
评论： Walter Roberson 2020-3-5
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Robin Li
Robin Li 2020-3-5
And also, not only abs(A(1)-B(1)) is <= 1; it can also abs(A(2)-B(1)) is <= 1. Are there easy ways to do so?
Walter Roberson
Walter Roberson 2020-3-5
Are you to produce a vector the same size as A? A vector the same size as B? Are you permitted to use vectorized operations at all?

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Amit
Amit 2020-3-5
We can do it in this way :
A = [1 2 3]; B = [2 4 5];
LenA = 1;
while LenA <= length(A)
if(A(LenA)-B)<=1
out = true;
break
else
out = false;
end
LenA =LenA+1;
end
disp(out)
Hope it helps.
  1 个评论
Walter Roberson
Walter Roberson 2020-3-5
We discourage people from prividing complete solutions to homework problems.
Also, this code does not impliment the original requirement to use abs().
if(A(LenA)-B)<=1
A(LenA) would be a scalar, but B is a vector, so A(LenA)-B would be a vector, and the result of comparing to 1 would be a vector. if statements are only considered true if all elements of the array of values being tested are non-zero. The above code is therefore looking to see whether there is some element of A that is within 1 of every element of B. It is not at all clear to me that is what the homework is intended to test.

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