How to do this while loop

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Robin Li 2020-3-5

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/509147-how-to-do-this-while-loop

评论： Walter Roberson 2020-3-5

采纳的回答： Amit

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Robin Li 2020-3-5

And also, not only abs(A(1)-B(1)) is <= 1; it can also abs(A(2)-B(1)) is <= 1. Are there easy ways to do so?

Walter Roberson 2020-3-5

Are you to produce a vector the same size as A? A vector the same size as B? Are you permitted to use vectorized operations at all?

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Amit 2020-3-5

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We can do it in this way :

A = [1 2 3]; B = [2 4 5];
LenA = 1;
while LenA <= length(A)
    if(A(LenA)-B)<=1
        out = true;
        break
    else
        out = false;
    end
    LenA =LenA+1;
end
disp(out)

Hope it helps.

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Walter Roberson 2020-3-5

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We discourage people from prividing complete solutions to homework problems.

Also, this code does not impliment the original requirement to use abs().

if(A(LenA)-B)<=1

A(LenA) would be a scalar, but B is a vector, so A(LenA)-B would be a vector, and the result of comparing to 1 would be a vector. if statements are only considered true if all elements of the array of values being tested are non-zero. The above code is therefore looking to see whether there is some element of A that is within 1 of every element of B. It is not at all clear to me that is what the homework is intended to test.

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