Yes, just removing the for loop because this loop doesn't do anything in your code.
Reshape the vector as indexed matrix.
1 次查看(过去 30 天)
显示 更早的评论
I need to reshape each row vector in 'x' to the 2D matrix as indexed in 'idx'. I have written the code and working fine. But it takes more time as the number of rows in x is high. Is there any way to reduce the execution time?
x=ones(4732,28000);
idx = buffer(1:28000,10,5,'nodelay');
tic
for i=1:4732
x1=x(i,:);
y=x1(idx);
end
toc
Elapsed time is 1.450427 seconds.
0 个评论
回答(1 个)
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!