How to integrate a signal sawtooth?

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moustafa abada
moustafa abada 2020-3-6
评论： Star Strider 2020-3-6
I'm integrrating the signal sawtooth using the function "integral" such that "0" min limit and "i" is the max limit to get values of theta to plot it with time but there is an error 'Invalid expression. When calling a function or indexing a variable, use parentheses. Otherwise, check for mismatched delimiters.'
Can you help please ?
fs = 1000;
kf=1000;
t = 0:1/fs:2;
signal = @(tt) sawtooth(pi*2*tt+pi);
theta=[];
for i = (0:1/fs:2)
theta=2*pi*kf*integral(signal,0,i);
end
plot(t,theta[i])

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采纳的回答

Star Strider
Star Strider 2020-3-6
Try this:
fs = 1000;
kf=1000;
t = 0:1/fs:2;
signal = @(tt) sawtooth(pi*2*tt+pi);
theta=zeros(size(t));
for i = 1:numel(t)
theta(i)=integral(signal,0,t(i));
end
figure
plot(t,theta)
It is necessary here to subscript ‘t’ and ‘theta’ in the loop to create the desired vectors.

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