2D plot by including third parameter as colorbar

19 次查看（过去 30 天）
Anju K Joshi
Anju K Joshi 2020-3-10
评论： Anju K Joshi 2020-3-23
I have 3 matrices (X Y and Z). Among these X and Z are of same size, that means same number of rows and columns. the second one Y is a column vector with same number of rows of X and Z. I need to create a plot between these three.The x axis will be matrix X and y axis will be vector Y. The values in Z matrix corresponding to X and Y matrix is represented in the plot and the values should show as colorbar.
Can anyone help please? I will be so grateful.
[SL: the text was formatted as code. Formatted it as text instead.]
  2 个评论
Hank
Hank 2020-3-10
see this thread: https://www.mathworks.com/matlabcentral/answers/5042-how-do-i-vary-color-along-a-2d-line
Anju K Joshi
Anju K Joshi 2020-3-12
I got the figure like this.. the problem is that the left and right portion should be blue and middle portion should be red according to the value..but the left side is only blue and middle and right side is blue...according to colourbar and the value in Z axis is near to blue in colorbar

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Piyush Lakhani
Piyush Lakhani 2020-3-12
The simplest way to doing this is by using the 'surf' or 'contourf' functions.
But, for that you need to create m x n matrix for all three variables. First convert Y from column to Row and then use 'meshgrid' comand to create Y as same size as X.
Y=Y';
Y=meshgrid(Y);
Y=Y(length(X),:);
Then use countourf
contourf(X,Y,Z)
  2 个评论
Anju K Joshi
Anju K Joshi 2020-3-17
but using this code, both X and Z is getting plotted in the figure as line and shade respectively. I need to display only Z matrix as line and I need shade in between all lines.
Anju K Joshi
Anju K Joshi 2020-3-23
I created a contour plot and made it two dimension using view(0,90).
Thanks for the help

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Line Plots 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by