how would i get a while loop to repeat this code 26 times?

2020 3 15
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更新时间：2020 3 15
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shiptext= [22 6;38 21;24 36;2 30;6 2;15 31;22 15;24 15;10 33;29 11;32 15;29 21;31 4;25 27;29 27;10 11;35 17;15 14;22 20;21 29;23 22;3 22;33 9;8 38;10 4;11 29]
shipnumber= size(shiptext,1)
disp(shipnumber)
plot(shiptext(:,1),shiptext(:,2),'.');
idr1=randi(26,1,1);
row1=shiptext(idr1,:);
idr2=randi(26,1,1);
row2=shiptext(idr2,:);
a=row2-row1
xdistance=a(1)
ydistance=a(2)
distance=sqrt(((xdistance)^2)+((ydistance)^2));
disp(distance)

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Ameer Hamza
Ameer Hamza 2020-3-15
What do you want to repeat 26 times? You can repeat a piece of code 26 times using for loop.
for i=1:26
% your code
end
Josh Williams
Josh Williams 2020-3-15
I need the code to run 26 times to give me 26 answers for distance at the end (each time generating a different random matrix) however im only allowed to use while loops.

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Sriram Tadavarty
Sriram Tadavarty 2020-3-15

0 个投票

Hi Josh,
You can do the following
i = 1; % loop index
while i <= 26
shiptext= [22 6;38 21;24 36;2 30;6 2;15 31;22 15;24 15;10 33;29 11;32 15;29 21;31 4;25 27;29 27;10 11;35 17;15 14;22 20;21 29;23 22;3 22;33 9;8 38;10 4;11 29]
shipnumber= size(shiptext,1)
disp(shipnumber)
plot(shiptext(:,1),shiptext(:,2),'.');
idr1=randi(26,1,1);
row1=shiptext(idr1,:);
idr2=randi(26,1,1);
row2=shiptext(idr2,:);
a=row2-row1
xdistance=a(1)
ydistance=a(2)
distance(i)=sqrt(((xdistance)^2)+((ydistance)^2)); % Stores distance for each loop index
%disp(distance)
i = i+1;
end
disp (distance)
This should do what you have asked for.
Regards,
Sriram

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