What can I do to large scale array?
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Hi, I met a problem dealing with very large scale data.
My server's limit is:
>> [str,maxsize]=computer
str =
GLNXA64
maxsize =
2.8147e+14
And I define an array like ones(3^N, 3^N, N+1, 1000,'uint16') where N=13.
The error shows :
Error using ones Maximum variable size allowed by the program is exceeded.
My question is, can I use another data type to avoid this problem? I realize it is a very large scale to Matlab.
Thanks.
2 个评论
Honglei Chen
2012-10-17
What do you intended to do with such a large matrix? It's one thing to be able to create a matrix, but I assume you also want to do some operation on it? Do you have to create all elements at once?
C Zeng
2012-10-18
采纳的回答
There are two limiters: data type and addressable memory. The data type will affect how much memory is needed. It can be solved by getting more RAM (although for the sizes you are talking about, I doubt that's a realistic solution).
The addressable memory, for all practical purposes, can't be solved. That is unless you had a 128 bits or more computer. Even then you would need to ask the Mathworks to modify Matlab to be able to use it. I don't know exactly how Matlab handles memory, but even though your matrix has less elements that the theoretical maximum in a 64 bit system (2^64-1), it still has more than what a Matlab matrix can handle (see previous link).
Both are limiters in your case, you can't create an array that large because you have more values than addressable memory (in Matlab), and even if that wasn't a problem, you would need too much memory.
What do you want to do with so large an array? A sparse array would help you reduce the size. To be of more help, more details are needed.
5 个评论
C Zeng
2012-10-17
José-Luis
2012-10-18
If there are a lot of zeros in your array, it might pay off to use a sparse array.
doc sparse
C Zeng
2012-10-18
Walter Roberson
2012-11-2
The limit for addressable memory on Intel's x64 current chips is 40 bits; that array would require 55 bits worth of data. Sparse arrays might help but more likely is that you will need to redesign the algorithm.
C Zeng
2012-11-7
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