How to count consuctive 0's inbetween values of 1

Question

Chris E. 2012-10-17

1
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/51119-how-to-count-consuctive-0-s-inbetween-values-of-1

I have really long code that does what I want, but I wanted to try to find a faster code to do this, for loop is taking forever. for example I have a vector of:

count = [0; 1; 0; 0; 0; 1; 0; 1; 1; 1; 0; 0; 0; 1; 0; 1; 1; 0; 0]

What I would like for an answer is the consecutive 0's between the ones... so,

ans =

Here is what I have to do it, (count coming in is the 1 and 0 vector list), the output is "store":

for m = 1:size(count,1)

    store = 0;
    countlast = 0;
    j = 0;
    if (sum(count)>=1)
        for n = 1:size(count,1)
            if count(n) == 0
                countlast = countlast + 1;
            else
                j = j + 1;
                store(j) = countlast;
                countlast = 0;
            end
        end
        j = j + 1;
        store(j) = countlast;
    end

end

store'

If there is a faster way of doing this Please help me out! Thanks, Chris

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Answer 1

Kye Taylor 2012-10-17

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https://ww2.mathworks.cn/matlabcentral/answers/51119-how-to-count-consuctive-0-s-inbetween-values-of-1#answer_62278

编辑：Kye Taylor 2012-10-17

在 MATLAB Online 中打开

This is a fun one.

Try

count = reshape(count,1,[]); % make it a row vector
store = [nnz(cumsum(count)==0),...
         diff(find(count))-1,...
         nnz(cumsum(count)==max(cumsum(count)))-1]

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Chris E. 2012-10-18

Thanks a ton! glad you found it fun...

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Answer 2

Sean de Wolski 2012-10-17

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/51119-how-to-count-consuctive-0-s-inbetween-values-of-1#answer_62280

在 MATLAB Online 中打开

v = [0; 1; 0; 0; 0; 1; 0; 1; 1; 1; 0; 0; 0; 1; 0; 1; 1; 0; 0;1];
vzcount = diff(find([1;v;1]))-1;  %find ones in a [1;v;1] vector and take the difference -1
%Remove zeros from first or last element
if vzcount(1)==0;
  vzcount = vzcount(2:end);
end
if vzcount(end) == 0;
  vzcount = vzcount(1:end-1);
end