solving for a single unknown variable(non-linear equation)

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shunmugam hemalatha 2020-3-17

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https://ww2.mathworks.cn/matlabcentral/answers/511288-solving-for-a-single-unknown-variable-non-linear-equation

评论： Ameer Hamza 2020-3-18

E=0.0313; E^2=0.00098; E^3=0.00003;

d=5000; K=100; h=5; lamda=0.5; C=25; S=50; P=0.05;

a=1-E;

b=((2*y)+(y*E)+1))^2;

y=(1/a)*(1/b)*((2*d*S)-(2*d*C)-(2*d*lamda)+(4*D*K)+(2*d*K*E)-(2*h*y^2)+(2*h*y^2*E^2)-(h*y^2*E)+(h*y^2*E^3)-(2*h*y)+(2*h*y*E^2);

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Answer 1

Ameer Hamza 2020-3-17

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https://ww2.mathworks.cn/matlabcentral/answers/511288-solving-for-a-single-unknown-variable-non-linear-equation#answer_420513

编辑：Ameer Hamza 2020-3-17

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You need to use fsolve to solve such an equation. First, define a function handle and then use fsolve

E=0.0313;
d=5000; K=100; h=5; lamda=0.5; C=25; S=50; P=0.05;
a=1-E;
b=@(y) ((2*y)+(y*E)+1)^2;
f = @(y) y - (1/a)*(1/b(y))*((2*d*S)-(2*d*C)-(2*d*lamda)+(4*d*K)+(2*d*K*E)-(2*h*y^2)+(2*h*y^2*E^2)-(h*y^2*E)+(h*y^2*E^3)-(2*h*y)+(2*h*y*E^2));
y_solution = fsolve(f, 0);