Fahrenheit function but confused on the output.

Question

Ireedui Ganzorig 2020-3-18

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/511481-fahrenheit-function-but-confused-on-the-output

评论： Shannon Wagoner 2020-4-8

Hello MATLAB community,

I feel like I did everything right, but the function output is really confusing me. Or did I do everything wrong in the first place?

This is function output.

0 = solid

1 = liquid

2 = gas

Below is my code.

function [state] = h2oState(tempF)
C = input('Please enter your Celsius value to be converted into Fahrenheit ');
tempF = 9/5 * C + 32;
if tempF <= 32
    
    disp(['The Fahrenheit temperature is ',num2str(tempF)])
    disp('solid')
elseif tempF > 212
    
    disp(['The Fahrenheit temperature is ',num2str(tempF)])
    disp('gas')
 
else
    
    disp(['The Fahrenheit temperature is ',num2str(tempF)])
    disp('liquid')
end
end

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Answer 1

Rik 2020-3-18

1
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https://ww2.mathworks.cn/matlabcentral/answers/511481-fahrenheit-function-but-confused-on-the-output#answer_420682

在 MATLAB Online 中打开

You are overwriting the input to your function by asking the user for the temperature in Celsius. You are also not assigning any value to your output variable state.

You probably want something like this:

function state = h2oState(C)
tempF = 9/5 * C + 32;
if tempF <= 32
    disp(['The Fahrenheit temperature is ',num2str(tempF)])
    disp('solid')
    state=0;
elseif tempF > 212
    disp(['The Fahrenheit temperature is ',num2str(tempF)])
    disp('gas')
    state=2;
else
    disp(['The Fahrenheit temperature is ',num2str(tempF)])
    disp('liquid')
    state=1;
end
end