Using delay seq to shift data with different delay conditions

2020 3 19
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更新时间：2020 3 20
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Hi! I have a matrix that has 10 columns and 50 rows. I want to introduce a delay in columns 2,3 and 4, and then again in columns 7,8,9 and 10. In column 2, I want a delay by one sample, in column 3 I want a delay by 2 samples, in column 4 I want a delay of 3 samples, and similarly in columns 7,8,9 and 10 I want delays of 4,5,6 and 7 samples. Is there a way I could use delayseq to automate this process? Thanks in advance!

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Sriram Tadavarty
Sriram Tadavarty 2020-3-19
May i know what does delay mean here? Any small example for the situation.
Zuha Yousuf
Zuha Yousuf 2020-3-19
Hi! Thanks for responding! By delay, I mean that I want to shift the samples down the columns. For example, suppose I had a matrix [2 3 4; 5 6 7; 8 9 10 ]. I want to shift the second and third columns down. For example, I want to shift the second column down by introducing 1 zero. I want to shift the third column down by introducing 2 zeros. Basically I want to do what circshift does, WITHOUT the circular aspect.
Sriram Tadavarty
Sriram Tadavarty 2020-3-19
So, to see if i understand correctly, you want the output to be [2 0 0;5 3 0;8 6 4;0 9 7;0 0 10], for the input matrix you placed. Am i right?

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Sriram Tadavarty
Sriram Tadavarty 2020-3-19

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Hi Zuha,
Here is the code for what is looked for:
a = rand(50,10);
shift = [0 1 2 3 0 0 1 2 3 4]; % Use the shift required for eah column
a1 = zeros(54,10);
a1(1:50,shift==0) = a(:,shift==0);
a1(2:51,shift==1) = a(:,shift==1);
a1(3:52,shift==2) = a(:,shift==2);
a1(4:53,shift==3) = a(:,shift==3);
a1(5:54,shift==4) = a(:,shift==4);
% Or this can be done through loop
a2 = zeros(size(a,1)+max(shift),size(a,2));
for i = 1:size(a,2)
a2(shift(i)+1:size(a,1)+shift(i),i) = a(:,i);
end
Hope this helps.
Regards,
Sriram

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Zuha Yousuf
Zuha Yousuf 2020-3-19
Hi, that gives me this kind of matrix:
I see that columns 5 and 6 are both not being delayed. I want column 5 to not be delayed, and column 6 to be delayed. Is there any reason why this might be happening?
Sriram Tadavarty
Sriram Tadavarty 2020-3-20
编辑：Sriram Tadavarty 2020-3-20
Hi Zuha, In the shift variable provide the shift as non-zero for the sixth column and that would solve. The update to shift vector in the answer will help. Let me know if the sixth value changed from 0 to the value you want and you get the expected answer. And then, seeing the image below you don't want the number of rows to be changed, so after the loop, or after those calculations, update a1 = a1(1:50,1:10); and a2 = a(1:size(a,1),1:size(a,2)); Hope this helps.

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Zuha Yousuf
Zuha Yousuf 2020-3-19

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Basically, something like this. The first column after the one not being delayed should always have one 0, the next always have two 0s and so on. I've attached a picture for clarity.

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