Using delay seq to shift data with different delay conditions
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Hi! I have a matrix that has 10 columns and 50 rows. I want to introduce a delay in columns 2,3 and 4, and then again in columns 7,8,9 and 10. In column 2, I want a delay by one sample, in column 3 I want a delay by 2 samples, in column 4 I want a delay of 3 samples, and similarly in columns 7,8,9 and 10 I want delays of 4,5,6 and 7 samples. Is there a way I could use delayseq to automate this process? Thanks in advance!
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Sriram Tadavarty
2020-3-19
So, to see if i understand correctly, you want the output to be [2 0 0;5 3 0;8 6 4;0 9 7;0 0 10], for the input matrix you placed. Am i right?
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Sriram Tadavarty
2020-3-19
Hi Zuha,
Here is the code for what is looked for:
a = rand(50,10);
shift = [0 1 2 3 0 0 1 2 3 4]; % Use the shift required for eah column
a1 = zeros(54,10);
a1(1:50,shift==0) = a(:,shift==0);
a1(2:51,shift==1) = a(:,shift==1);
a1(3:52,shift==2) = a(:,shift==2);
a1(4:53,shift==3) = a(:,shift==3);
a1(5:54,shift==4) = a(:,shift==4);
% Or this can be done through loop
a2 = zeros(size(a,1)+max(shift),size(a,2));
for i = 1:size(a,2)
a2(shift(i)+1:size(a,1)+shift(i),i) = a(:,i);
end
Hope this helps.
Regards,
Sriram
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Sriram Tadavarty
2020-3-20
编辑:Sriram Tadavarty
2020-3-20
Hi Zuha, In the shift variable provide the shift as non-zero for the sixth column and that would solve. The update to shift vector in the answer will help. Let me know if the sixth value changed from 0 to the value you want and you get the expected answer. And then, seeing the image below you don't want the number of rows to be changed, so after the loop, or after those calculations, update a1 = a1(1:50,1:10); and a2 = a(1:size(a,1),1:size(a,2)); Hope this helps.
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