differential equation 2DOF

1 次查看(过去 30 天)
------------------------------------------------------
function homework2 = main2(t,X1,X2)
global m1 c1 k1 m2 c2 k2
M=[m1 0;0 m2];
C=[c1+c2 -c2; -c2 c2];
K=[k1+k2 -k2; -k2 k2];
F=[3*cos(t);10*cos(3*t)];
X=[X1;X2];
homework2=M*X(3)+C*X(2)+K*X(1)-F;
end
-------------------------------------------------------
tspan= 0:0.1:50 ;
X0 = [0 0;0 0] ;
[t, X] = ode45(@main2, tspan, X0);
plot(X1,X2)
I do it here and it 's ain't working....

采纳的回答

Birdman
Birdman 2020-3-20
You may try Symbolic Toolbox to solve the problem. Run the attached script to see the result.
  5 个评论
alsgud qor
alsgud qor 2020-3-21
um sorry.because of time lag, I just recieved it. let me ask some Q
  1. dydt = zeros(4,1); what does it mean?
  2. dydt(2) = (-k1/m1)*y(1)+(-c1/m1)*y(2)+F1; this part should be changed into 'F1/m1'? same with dydt(4)
Birdman
Birdman 2020-3-23
  1. It means that I created a vector of zeros with 4 elements.
  2. Yes exactly, I missed that.

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Programming 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by