Continuously update variable in function

Question

Steven Strange 2020-3-20

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/511970-continuously-update-variable-in-function

评论： Steven Strange 2020-3-20

采纳的回答： darova

在 MATLAB Online 中打开

Hi Guys, CODE BELOW

I have a function where I have the variable coun, coun is calculated

I then have a function which runs that function multiple times for a given number.

What I would like to do is run the function twice, so lets say i run it first time and then get coun = -1 i want to then use that value of coun and not start again at zero. Could someone please help me with this, thanks Steven.

CODE BELOW for calculation of count.

function [x,money] = winnings4(x)
i0 = (randi(length(x)));
j0 = (randi(length(x)));
k0 = (randi(length(x)));
while j0==i0 
    j0 = (randi(length(x)));
end
while k0==j0 
    while k0==i0
    k0 = (randi(length(x)));
    end
    if k0==j0
    k0 = (randi(length(x)));
    end 
end
PlayersHand = [x(i0),x(j0)]
DealersHand = [x(k0)]
a = x(i0)
b = x(j0)
c = x(k0)
coun = 0;
if a < 7 && a >= 2
    coun = coun + 1
end
if a < 10 && a > 6
    coun = coun + 0
end
if a == 10
    coun = coun - 1
end
if a == 1
    coun = coun - 1
end
if b < 7 && b > 2
    coun = coun + 1
end
if b < 10 && b > 6
    coun = coun + 0
end
if b == 10
    coun = coun - 1
end
if b == 1
    coun = coun - 1
end
if c < 7 && c > 2
    coun = coun + 1
end
if c < 10 && c > 6
    coun = coun + 0
end
if c == 10
    coun = coun - 1
end
if c == 1
    coun = coun - 1
end
x(i0) = 0;
x(j0) = 0;
x(k0) = 0; 
x = x(x~=0)
%%----------------------------------------CODE FOR FUNCTION TO RUN ABOVE MULTIPLE TIMES BELOW:----------------------%%
function run4 = m()
v = [1,1,1,1,2,2,2,2,3,3,3,3,4,4,4,4,5,5,5,5,6,6,6,6,7,7,7,7,8,8,8,8,9,9,9,9,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10]; 
deck = [v,v,v,v,v,v]; % 6 decks
y = zeros(1,100);
for k = 1:2 
[deck,y(k)] = winnings4(deck);
if length(deck) < 78 
run4 = sum(y); 
p = length(deck); 
q = k; 
return
end
end
run4 = sum(y);
end 