‘as you can see Y_out has 1 row and 4 column.’
We cannot see any of that because they are not provided.
This could work, although I cannot even test it or simulate it because I do not know what ‘Y_out’ is:
for l=1:4
[symNum,symDen] = numden(Y_out(1,l)); %Get num and den of Symbolic TF
TFnum = sym2poly(symNum); %Convert Symbolic num to polynomial
TFden = sym2poly(symDen); %Convert Symbolic den to polynomial
sys =tf(TFnum,TFden);
figure
pzplot(sys)
end
