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For example,
Given the matrix:
matrix =
18 4
12 11
11 12
4 18
I want to get rid of the repeated values that happen after the first two rows to just get
matrix =
18 4
12 11
4 个评论
Ajay Kumar
2020-3-22
What if 1 number matches with other in a diffetent row?
MR
2020-3-22
Rik
2020-3-25
In response to your flag ("I posted an unclear question and did not receive help"):
You did receive help. Why don't you try describing the question more clearly if you think that is the problem?
回答（2 个）
Rik
2020-3-25
I think the code below is what you need. There may be much more efficient methods, but this will do as long as this will not be the bottleneck in your workflow.
clc
v=[18 4
12 11
11 12
4 18];
remove_duplicate_rows(v)
v=[23 2
22 4
21 6
19 8
14 14
8 19
6 21
4 22
2 23];
remove_duplicate_rows(v)
function v=remove_duplicate_rows(v)
keeprows=false(size(v,1),1);
keeprows(1)=true;
for r=2:numel(keeprows)
%check if the values are already in the rows that we want to keep
%compare against numel(unique(v(r,:))) to catch repeated values
if numel(setdiff(v(r,:),v(keeprows,:)))==numel(unique(v(r,:)))
keeprows(r)=true;
end
end
v=v(keeprows,:);
end
0 个评论
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2021-8-20
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