I want to integrate froma function

2 次查看（过去 30 天）
Rodrigo Blas
Rodrigo Blas 2020-3-22
评论： Ameer Hamza 2020-3-22
function prob7f=xequil(x,cao,ep,k2,kc,Fao)
ca=cao*(1-x)./(1+ep*x);
cb=cao*(1-x)./(1+ep*x);
cc=2*cao*x./(1+ep*x);
ra=-(k2*(ca-(cb*cc)./kc));
prob7f=Fao./(-ra);
end
z=@xequil;
volpfreq=integral(z,0,xf);
>> Jallohw5p7
Not enough input arguments.
Error in xequil (line 3)
ca=cao*(1-x)./(1+ep*x);
Error in integralCalc/iterateScalarValued (line 314)
fx = FUN(t);
Error in integralCalc/vadapt (line 132)
[q,errbnd] =
iterateScalarValued(u,tinterval,pathlen);
Error in integralCalc (line 75)
[q,errbnd] = vadapt(@AtoBInvTransform,interval);
Error in integral (line 88)
Q = integralCalc(fun,a,b,opstruct);
Error in Jallohw5p7 (line 32)
volpfreq=integral(z,0,xf);
All other varables are defined, except x of course, which is the variables I want to solve for.
  2 个评论
Ameer Hamza
Ameer Hamza 2020-3-22
What are values of cao,ep,k2,kc,Fao? Where are they defined? You need to define them inside the function.
Rodrigo Blas
Rodrigo Blas 2020-3-22
%%Data
T1=50+273.15; %%k
T2=127+273.15; %%k
Fao=2.5; %%mol/min
P=10; %%atm
k1=10^-4; %%min^-1
R=8.314; %j/k*mol
R1=8.206*10^-5*1000; %%atm*dm^3/K*mol
E=85*1000; %%j/mol
kc=.025; %%mol/dm^2
alpha=.001; %%dm^3
t=3*60; %%min
Nao=450;
xf=.90;
xo=0;
%%Calculated Data
k2=k1*exp(E/R*(1/T1-1/T2)); %%min^-1
cao=P/(T2*R1); %%mol/dm^3
ep=2+1-1;
xe=jallohw5p7f(cao,ep,kc,xo);
xfe=xe*.9;
pfrxeq=@xequil;
volcstr=(Fao*xf)*(1+ep*xf)/(k2*cao*(1-xf)); %%dm^3
fun=@(x) Fao/(cao*k2)*(1+ep*x)./(1-x);
z=@xequil;
%%funeeqpfr=@(x) Fao/(-ra);
volpfreq=integral(z,0,xf);
volpfr=integral(fun,0,xf); %%dm^3
t=3*60;
Nao=450;
v7e=Nao/(t*k2*cao)*log(1/(1-xf));
[x,y]=ode45(@(x,y) jallohwfun7(alpha,ep,y,cao,k2,Fao),[0 500],[1 0]);
%%funeq=@(x) Fao./(-(k2*cao/(1+ep*x)*((1-x)-(4*cao^2*x^3)/((1+ep*x)^2)*kc)));
%%volpfreq=integral(funeq,0,xf);
plot(x,y(:,1),'r','LineWidth',1);
hold on;
plot(x,y(:,2),'k','LineWidth',1);
legend('Pressure', 'Conversion');
xlabel('Volume [dm^3]');
ylabel('Pressure [atm] & Conversion');
title('Pressure and Conversion vs Volume ');
Here is my whole script..
Really? I cant pass them through the function?

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Ameer Hamza
Ameer Hamza 2020-3-22
The integral function should be called like this
z=@(x) xequil(x, cao, ep, k2, kc, Fao);
volpfreq=integral(z,0,xf);
Also change the following line in the function xequil
ra=-(k2*(ca-(cb*cc)./kc));
with
ra=-(k2.*(ca-(cb.*cc)./kc));
  2 个评论
Rodrigo Blas
Rodrigo Blas 2020-3-22
function prob7f=xequil(x,cao,ep,k2,kc,Fao)
ca=cao*(1-x)./(1+ep*x);
cb=cao*(1-x)./(1+ep*x);
cc=2*cao*x./(1+ep*x);
ra=-(k2.*(ca-(cb.*cc)./kc));
prob7f=(Fao/(-ra));
end
z=@(x) xequil(x,cao,ep,k2,kc,Fao);
volpfreq=integral(z,0,xf);
>> Jallohw5p7
Error using /
Matrix dimensions must agree.
Error in xequil (line 8)
prob7f=(Fao/(-ra));
Error in Jallohw5p7>@(x)xequil(x,cao,ep,k2,kc,Fao)
Error in integralCalc/iterateScalarValued (line 314)
fx = FUN(t);
Error in integralCalc/vadapt (line 132)
[q,errbnd] =
iterateScalarValued(u,tinterval,pathlen);
Error in integralCalc (line 75)
[q,errbnd] = vadapt(@AtoBInvTransform,interval);
Error in integral (line 88)
Q = integralCalc(fun,a,b,opstruct);
Error in Jallohw5p7 (line 30)
volpfreq=integral(z,0,xf);
This is the new error I get
Ameer Hamza
Ameer Hamza 2020-3-22
You also changed the last line
prob7f=(Fao/(-ra));
change it back to
prob7f=(Fao./(-ra));

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Matrix Computations 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by