Classification result of matrix row multiplication

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Alice Zurock
Alice Zurock 2020-3-22
编辑： Alice Zurock 2020-3-23
1- Is there any less than -1 (<-1 )or bigger than (>1) Result1 or Result2, If there is ...-3, -2 ,2,3,4... Result1 or Result2 say that this row is BAD, Now print this row as a BAD(Because I need to now how many BAD row are there?).
2- If Result 1 and Result 2 is between: -1, 0 or 1, Now print this row as a GOOD(Because I need to now how many GOOD row are there?).
3- If Result 1 and Result 2 is: -1 or 0, Now print this row as a VERY GOOD(Because I need to now how many VERY GOOD row are there?).
And I need to check for that Length 4,5,6..... N matrixes.
PS For length 4 I need to look at 3 times circular shift because 4. circular shift same as original row. Length 5, need to look at 4 times circular shift, so on...

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Sriram Tadavarty
Sriram Tadavarty 2020-3-22
编辑：Sriram Tadavarty 2020-3-23
Hi Alice,
Provided you have a matrix as defined for length N. Here is the code that would work for length equal to 2.
matrix = [1 1 1; 1 1 -1; 1 -1 -1; 1 -1 1; -1 1 1; -1 1 -1; -1 -1 -1; -1 -1 1];
n = size(matrix,2);
% Use a for loop
for i = 1:size(matrix,1)
tmpMat = matrix(i,:); % Assigns each row of the matrix
for j = 1:n-1
circMat = circshift(tmpMat,-j); % Perform circular shift
r(i,j) = sum(tmpMat.*circMat); % For each row and circular shift
end
% Perform display checks
if any(r(i,:) < -1) || any(r(i,:)>1)
disp('BAD')
end
if all(r(i,:) >= -1) && all(r(i,:) <= 1)
disp('GOOD')
end
if all(r(i,:) >= -1) && all(r(i,:) <= 0)
disp('VERY GOOD')
end
end
Hope this helps.
Regards,
Sriram
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Sriram Tadavarty
Sriram Tadavarty 2020-3-23
编辑：Sriram Tadavarty 2020-3-23
Hi Alice, you are not updating the counter variable, in the latest code, Update this and it would solve. If the answer is helpful, do accept it
bad = 0;
good = 0;
verygood = 0;
len=3;
N = 2^len;
binary = de2bi(N-1:-1:0); % Convert decimal numbers in to binary
binary(binary==0) = -1; % Replace the values of 0 with -1
n = size(binary,2);
for i = 1:size(binary,1)
MyMatrix = binary(i,:); % Assigns each row of the matrix
for j = 1:n-1
circMat = circshift(MyMatrix,-j); % Perform circular shift
result(i,j) = sum(MyMatrix.*circMat); % For each row and circular shift
end
if any(result(i,:) < -1) || any(result(i,:) > 1)
disp(['Bad' num2str(i)])
bad = bad+1; % Incremet the bad variable
end
if all(result(i,:) >= -1) && all(result(i,:) <= 1)
disp(['Good' num2str(i)])
good = good+1; % Increment the good variable
end
if all(result(i,:) >= -1) && all(result(i,:) <= 0)
disp(['Very Good' num2str(i)])
verygood = verygood+1; % Increment verygood variable
end
end
Hope this helps.
Regards,
Sriram
Sriram Tadavarty
Sriram Tadavarty 2020-3-23
Yes, i did. I get 6 good rows and 6 very good rows. Can you clear the variables and try the code?
The output i get
Bad1
Good2
Very Good2
Good3
Very Good3
Good4
Very Good4
Good5
Very Good5
Good6
Very Good6
Good7
Very Good7
Bad8

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