Issue in using splitapply to plot data

2 次查看(过去 30 天)
Hi,
I have an array with 14 columns. Column 3 contains groups of numbers. I would like to plot column 1 vs. column 4 for each group of column 3. I have written the following code,
G = findgroups(val(:, 3));
splitapply(@plot, val(:, 1), val(:, 4), G);
From my data, I should be getting 6 plots within the figure. But I am getting only a single plot. So what is the issue in my code?
Also how to write legend using splitapply?
Thanks.

采纳的回答

Star Strider
Star Strider 2020-3-23
One approach:
D = load('val.mat');
val = D.val;
G = findgroups(val(:, 3));
figure
hold on
Y = splitapply(@(x){plot(x(:,[1 4]))}, val, G);
hold off
Another approach:
D = load('val.mat');
val = D.val;
G = findgroups(val(:, 3));
Y = splitapply(@(x){x(:,[1 4])}, val, G);
figure
hold on
for k = 1:numel(Y)
plot(Y{k})
end
hold off
grid
legend(compose('Group %d', 1:6), 'Location','eastoutside')
I prefer the second approach, however it is possible to use plot with splitapply, as the first approach demonstrates.
  8 个评论
vanrapa
vanrapa 2020-3-24
Channels will be in val(;,3) and it is working. Thanks

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