How to graph using a for loop
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I am asking for help in plotting a line graph in my "for" loop program. The program is able to run the calculations but I am not able to graph. Below is the code i have created.
clc
f=196.2;
fi=0; finc= pi/180; ff=pi/4
for x=0:pi/180:pi/4;
ac= (f*cos(x))/((sin(pi/6)*cos(x))+(cos(pi/6)*sin(x)))
fprintf('Force of AC is %7.2f\n',ac)
bc= ((ac*cos(pi/6))/cos(x))
fprintf('Force of BC is %7.2f\n',bc)
end
hold on;
xx=x(1:length(x));
plot(xx,ac)
采纳的回答
KSSV
2020-3-24
YOu need not use a loop as the other user has suggested you. If you use a loop, you need to intiilaize the array and save it in a loop as below:
f=196.2;
fi=0; finc= pi/180; ff=pi/4 ;
x=0:pi/180:pi/4;
ac = zeros(size(x)) ;
for i = 1:length(x)
ac(i)= (f*cos(x(i)))/((sin(pi/6)*cos(x(i)))+(cos(pi/6)*sin(x(i))))
fprintf('Force of AC is %7.2f\n',ac)
bc= ((ac*cos(pi/6))/cos(x(i)))
fprintf('Force of BC is %7.2f\n',bc)
end
plot(x,ac)
更多回答（1 个）
Sriram Tadavarty
2020-3-24
Hi Jose,
This code need not require a for loop. The following can be done to get the same result:
clc
f=196.2;
fi=0; finc= pi/180; ff=pi/4
x=0:pi/180:pi/4;
ac= (f*cos(x))./((sin(pi/6)*cos(x))+(cos(pi/6)*sin(x)))
fprintf('Force of AC is %7.2f\n',ac)
bc= ((ac*cos(pi/6))./cos(x))
fprintf('Force of BC is %7.2f\n',bc)
hold on;
plot(x,ac)
Hope this helps.
Regards,
Sriram
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