Matlab app designer can't go further than the first dropdown value

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farzad
farzad 2020-3-24
评论： Sean de Wolski 2020-4-16
Hi All
I have made an app with a dropdown and a push button. I should choose a value from dropdown and based on that the pushbutton will run a certain code pasted under it. let's say the dropdown values are 1,2,3
the problem is :
the app works fine If I choose the first value on dropdown menu and use the
if app.ConfigDropDown.Value == '1'
elsif app.ConfigDropDown.Value == '2'
elsif app.ConfigDropDown.Value == '3'
end
only if I choose the 1 , the code could run. otherwise it will give this error :
Matrix dimensions must agree.
Error in app/ExecuteButtonPushed (line 40)
if app.ConfigDropDown.Value == '2'
Error using matlab.ui.control.internal.controller.ComponentController/executeUserCallback (line 309)
Error while evaluating Button PrivateButtonPushedFcn.

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采纳的回答

Sean de Wolski
Sean de Wolski 2020-3-24
编辑：Sean de Wolski 2020-3-24
if app.ConfigDropDown.Value == '1'
elseif app.ConfigDropDown.Value == '2'
elseif app.ConfigDropDown.Value == '3'
end
You're missing some e's.
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farzad
farzad 2020-3-24
I don't know if putting a break in the app designer would really help since I can't see the output in the command prompt.
I only know that the app works if only the first drop down value is chosen, it does not work if I change it to other values
Sean de Wolski
Sean de Wolski 2020-4-16
You can see the value in the command prompt. Once you're stopped, type the value at the command prompt.

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