How do I create multiple column vectors from one big column vector?

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I have two column vectors, objx and objy, both of which contain 20,160 floats. I need to dice it up every 48 iterations to create voronoi figures. There will be 420 voronoi diagrams. How do I go about creating smaller vectors each of which containg 48 floats each to create these voronoi diagrams?
  5 个评论
Chad
Chad 2020-3-24
The column vectors are both 20160x1, there are 20160 rows and just 1 column, in each vector. Each row only has one numeric element. Its just 20160 numbers stacked on eachother.
Adam Danz
Adam Danz 2020-3-24
That's clear. The comma in 20,160 threw me off. There's no need to use a comma unless the number of digits is very large.

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Ameer Hamza
Ameer Hamza 2020-3-24
编辑:Ameer Hamza 2020-3-24
Try this
X = reshape(objx, 48, 420); % X is 48*420
Y = reshape(objy, 48, 420); % Y is 48*420
% loop will run 420 times
for i=1:size(X,2)
x = X(:,i); % x is 48*1
y = Y(:,i); % y is 48*1
voronoi(x,y);
% save the voronoi diagram
end
  11 个评论
Ameer Hamza
Ameer Hamza 2020-3-25
@Adam, thanks for suggesting the improvements. I am not sure whether it will make any difference for reshaping function that input is a row or column vector, as long as it has just one dimension. For higher-order matrices, we need to be careful about the arrangement of elements.
Adam Danz
Adam Danz 2020-3-25
That's true; a col or row vector will result in the same reshape. My mind may have still been on the possibility of cell arrays converted to matrices.

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