Generate matrix at each iteration
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Dear friend, please help me to generate a matrix 'yy' which stores matrix "xx" in each iteration.
%% direct search methods
clc;
clear variables;
delta=[2;2];
eps=10^(-3);
%% BOX EVOLUTINARY OPTIMIZATION METHOD
x0=[1;1];
% k=(delta(1)^2+delta(2)^2)^0.5;
for i=1:3
x1=x0+[1;-1];
x2=x0+[-1;-1];
x3=x0+[-1;1];
x4=x0+[1;1];
xx=[x0 x1 x2 x3 x4];
yy=xx();
f(1)=diremtd(x0);f(2)=diremtd(x1);
f(3)=diremtd(x2);f(4)=diremtd(x3);f(5)=diremtd(x4);
A=[f(1),f(2),f(3),f(4),f(5)];
k=min(A);
for j=1:5
if k==f(j)
tt=xx(:,j);
t=f(j);
end
end
x0=tt;
end
THANK YOU
采纳的回答
Image Analyst
2020-3-29
Instead of
yy=xx();
have
yy{i} = xx;
4 个评论
DEV
2020-3-29
Image Analyst
2020-3-29
Why not? It puts the whole array into the i'th cell of a cell array called yy. It should work. You asked "generate a matrix 'yy' which stores matrix "xx" in each iteration" and it certainly does that. Since what you asked is not what you want, what do you want? Do you want yy to be a 3-D array where each xx is one slice in a stack of 3 xx's? If so, declare yy before the loop:
yy = zeros(2, 5, 3);
then inside the loop, insert the current xx into slice i:
yy(:, :, i) = xx;
I can't run your code because I don't know what the diremtd() function or variable is.
DEV
2020-3-29
Image Analyst
2020-3-30
So are you ready to click the link to "Accept this answer"?
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