How do I create a for loop in MATLAB for this?
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Greeting everyone.
I have a these matrix: A is by the order of 10 by 3.
I want to do this calculation: B = (A-min(A))/[max(A)-min(A)]
After that I want B to be by the order of 10 by 3.
Is there a way where I can do a loop of this?
1 个评论
Walter Roberson
2020-3-30
Sure. You can deliberately create a loop or two to find the max and min, and you can deliberately create a loop or two to rescale. You do not need to do those things, but you can.
The trick for the vectorized form is that by default max and min work over only one dimension of a multidimensional array. See the documentation for how to change that to process all dimensions.
回答（2 个）
James Tursa
2020-3-30
编辑：James Tursa
2020-3-30
If you want to use the overall min and max, then just use A(:) for the calculations. E.g.,
B = (A-min(A(:)))/[max(A(:))-min(A(:))];
A(:) is shorhand for reshaping the variable into a column vector.
6 个评论
Chloe Sim
2020-3-30
James Tursa
2020-3-30
B will be the same size as A. Did you try the code?
Chloe Sim
2020-4-28
Walter Roberson
2020-4-28
Are you still required to do a loop for it? (If so, then go ahead and write a loop)
Chloe Sim
2020-4-29
Walter Roberson
2020-4-29
You can find the per-row min using min(A, [], 2) and you can find the per-row max using similar code. You can do the subtractions . But you should change the division from / to ./
The resulting expression should handle the entire matrix with no loops.
Steven Lord
2020-3-30
1 个投票
Use the normalize function with the 'range' method. No for loop is required.
1 个评论
Walter Roberson
2020-3-30
Or use the older, confusingly-named, mat2gray()
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2020-4-29
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