infinite series approximation program?

2012 10 21
2 个回答
更新时间：2014 10 13
4 次查看（30 天）

0 个投票

Hi all,
I am a beginner in MATLAB. My problem is about writing an infinite series approximation to a function f(1/5),that stops when the stopping criterion is met. Stopping criterion is given as Es=(0.5x10^2-n).Program should automatically terminate when Ea<Es. Also displaying the results in tabulated form which 1'st column shows the number of the terms, 2'nd column lists corresponding approximation for f(1/5), 3'rd column shows the true value of f(1/5),4'th and 5'th columns indicate the corresponding values of Et and Ea respectively.
Function and the series are like that: f(x)=7x^3/1-x=∑ 7x^n where initial value of n=3 and n goes to infinity.
I thought about using while loop with Ea<Es criterion, but i couldn't succeed to run the m-file.
Thanks for any immediate help, I have very short time to write this code for a project.

请先登录，再回答此问题。

回答（2 个）

Sachin Ganjare
Sachin Ganjare 2012-10-22

0 个投票

1 个评论
显示 -1更早的评论 隐藏 -1更早的评论

Otto
Otto 2012-10-22
First of all, thanks for your interest. The problem is not exactly writing an infinite series approximation in MATLAB. Keypoint of this problem is writing a program which stops when the stopping criterion Ea<Es is met. I've done something using While loop for Ea<Es criterion but something went wrong. My Question is mainly about writing this commands by true order in MATLAB.Here is my worksheet;
x=0.2; Es=(0.5*10.^(2-n)); Ea=(x(i)-x(i-1)/x(i))*100; s=0 n=3:inf; i=1:inf; while abs(Ea)>Es; s=s+7*x^n end
I have tried something like this but went wrong.
I will appreciate for any help,
Thank you again.

请先登录，再进行评论。

类别

在 帮助中心 和 File Exchange 中查找有关 Get Started with MATLAB 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by