infinite series approximation program?

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Otto 2012-10-21

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回答： Korhan Babacan Yilmaz 2014-10-13

Hi all,

I am a beginner in MATLAB. My problem is about writing an infinite series approximation to a function f(1/5),that stops when the stopping criterion is met. Stopping criterion is given as Es=(0.5x10^2-n).Program should automatically terminate when Ea<Es. Also displaying the results in tabulated form which 1'st column shows the number of the terms, 2'nd column lists corresponding approximation for f(1/5), 3'rd column shows the true value of f(1/5),4'th and 5'th columns indicate the corresponding values of Et and Ea respectively.

Function and the series are like that: f(x)=7x^3/1-x=∑ 7x^n where initial value of n=3 and n goes to infinity.

I thought about using while loop with Ea<Es criterion, but i couldn't succeed to run the m-file.

Thanks for any immediate help, I have very short time to write this code for a project.

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Otto 2012-10-23

anyone to solve this problem?

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Answer 1

Sachin Ganjare 2012-10-22

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/51481-infinite-series-approximation-program#answer_62769

Refer below link:

http://www.math.ucsd.edu/~bdriver/21d-f99/sequences-series/recursion.htm#B)

Hope it helps!!

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Otto 2012-10-22

First of all, thanks for your interest. The problem is not exactly writing an infinite series approximation in MATLAB. Keypoint of this problem is writing a program which stops when the stopping criterion Ea<Es is met. I've done something using While loop for Ea<Es criterion but something went wrong. My Question is mainly about writing this commands by true order in MATLAB.Here is my worksheet;

x=0.2; Es=(0.5*10.^(2-n)); Ea=(x(i)-x(i-1)/x(i))*100; s=0 n=3:inf; i=1:inf; while abs(Ea)>Es; s=s+7*x^n end

I have tried something like this but went wrong.

I will appreciate for any help,

Thank you again.

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