Finding decimal values without mod

2 次查看(过去 30 天)
Is it possible or is there any way to find a value in an array that is a decimal without using mod(or any other function)?
  5 个评论
KALYAN ACHARJYA
KALYAN ACHARJYA 2020-4-2
编辑:KALYAN ACHARJYA 2020-4-2
"For example, i want to separate the odd and even integers. I know there is easier ways,but i cant use functions only loops. (its a hw problem)"
You asked for with loop and without mod function, you can do multiple ways-
A=[1; 2; 3; 4; 5; 6; 7; 8]
m=1;n=1;
for i=1:length(A)
if rem(A(i),2)==0
EvenV(m)=A(i); % I want to store the Even integers
m=m+1;
else
OddV(n)=A(i); % i want to store the odd integers
n=n+1;
end
end
EvenV
OddV
James Tursa
James Tursa 2020-4-2
You are going to have to use some functions for this. Even the / you are currently using is a function. Which functions are explicitly forbidden?

请先登录,再进行评论。

回答(1 个)

Ameer Hamza
Ameer Hamza 2020-4-2
Right now, this is the only way I can think of to detect even and odd numbers without using any rounding functions and just a while loop. I suspect there might be more efficient solutions.
A=[1; 2; 3; 4; 5; 6; 7; 8];
Evens = [];
Odds = [];
for i=1:numel(A)
x = A(i);
tf = isEven(x);
if tf
Evens = [Evens x];
else
Odds = [Odds x];
end
end
function tf = isEven(x)
x = abs(x);
while true
x = x - 2;
if x == 0
tf = 1;
return
elseif x < 1
tf = 0;
return
end
end
end

类别

Help CenterFile Exchange 中查找有关 Loops and Conditional Statements 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by