Finding decimal values without mod
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Is it possible or is there any way to find a value in an array that is a decimal without using mod(or any other function)?
5 个评论
Ameer Hamza
2020-4-2
By decimal value, do you mean a fractional number. Do you want to seperate fractional numbers from integers?
James Tursa
2020-4-2
Please provide a small example of input and desired output.
Jose Grimaldo
2020-4-2
KALYAN ACHARJYA
2020-4-2
编辑：KALYAN ACHARJYA
2020-4-2
"For example, i want to separate the odd and even integers. I know there is easier ways,but i cant use functions only loops. (its a hw problem)"
You asked for with loop and without mod function, you can do multiple ways-
A=[1; 2; 3; 4; 5; 6; 7; 8]
m=1;n=1;
for i=1:length(A)
if rem(A(i),2)==0
EvenV(m)=A(i); % I want to store the Even integers
m=m+1;
else
OddV(n)=A(i); % i want to store the odd integers
n=n+1;
end
end
EvenV
OddV
James Tursa
2020-4-2
You are going to have to use some functions for this. Even the / you are currently using is a function. Which functions are explicitly forbidden?
回答（1 个）
Ameer Hamza
2020-4-2
Right now, this is the only way I can think of to detect even and odd numbers without using any rounding functions and just a while loop. I suspect there might be more efficient solutions.
A=[1; 2; 3; 4; 5; 6; 7; 8];
Evens = [];
Odds = [];
for i=1:numel(A)
x = A(i);
tf = isEven(x);
if tf
Evens = [Evens x];
else
Odds = [Odds x];
end
end
function tf = isEven(x)
x = abs(x);
while true
x = x - 2;
if x == 0
tf = 1;
return
elseif x < 1
tf = 0;
return
end
end
end
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2020-4-2
2020-4-2
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