how to store even and odd strings into 2 seperate vectors using mod function

names = ['c','a', 'b','z','x','s'];
oddlett = [];
evenlett = [];
[n,m] = size(names);
for i=1:m
    % convert letter to corresponding index in the alphabet
    ind = 1 + lower(names(i)) - 'a';
    
    if(mod(ind, 2) ==1)
       evenlett = [evenlett; names(i)];
    else
        oddlett = [oddlett; names(i)];
    end
    
end

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Answer 2

dpb 2020-4-4

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Whassup w/ this thing about alternative storage of odd/even indices all of a sudden???

<Answers/514742-how-to-separate-an-array-into-two> altho as pointed out there first, you don't need either a loop or the mod function to do it...

>> names=cellstr(['a':'e'].');
>> n1=names(1:2:end)
n1 =
  3×1 cell array
    {'a'}
    {'c'}
    {'e'}
>> n2=names(2:2:end)
n2 =
  2×1 cell array
    {'b'}
    {'d'}
>> 