Print out a one column array

2020 4 6
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更新时间：2020 4 6
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I have written the code below and it successfully prints out the average that I want PTS/G for all 20 values, however the matrix that is printed out has 19 extra columns of 0s. How do I delete those?
%average points per season
%ave = (PTS/G)
PTS =[539;1220;996;1485;1938;2019;2461;1557;1819;2832;2430;2323;2201;1970;2078;1616;2133;83;782;1161]
G = [71;79;50;66;68;80;82;65;66;80;77;82;82;73;82;58;78;6;35;66]
for ii=1:20
ave(ii)= PTS(ii)/G(ii)
disp(PTS(ii)/G(ii))
end

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Tommy
Tommy 2020-4-6

0 个投票

The extra columns may be left over from running
ave = (PTS/G)
If you clear your workspace, they should go away. However, if you want to divide each value in PTS by the corresponding value in G, you can just use
ave = PTS./G

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collegestudent
collegestudent 2020-4-6
And if I want to add the calculated ave values to have a year appear beside them increasing each time, how would I do that?
Tommy
Tommy 2020-4-6
编辑：Tommy 2020-4-6
Do you mean something like this?
PTS = [539;1220;996;1485;1938;2019;2461;1557;1819;2832;2430;2323;2201;1970;2078;1616;2133;83;782;1161];
G = [71;79;50;66;68;80;82;65;66;80;77;82;82;73;82;58;78;6;35;66];
ave = PTS./G;
yrs = (2000:2019)';
fprintf('%.2f avg points per game in %i\n', [ave yrs]')
collegestudent
collegestudent 2020-4-6
Yes! Exactly that, but including the for loop from before. Is that possible?
Tommy
Tommy 2020-4-6
Sure, maybe this?
PTS = [539;1220;996;1485;1938;2019;2461;1557;1819;2832;2430;2323;2201;1970;2078;1616;2133;83;782;1161];
G = [71;79;50;66;68;80;82;65;66;80;77;82;82;73;82;58;78;6;35;66];
yrs = (2000:2019)';
for ii = 1:numel(PTS)
fprintf('%.2f avg points per game in %i\n', PTS(ii)/G(ii), yrs(ii))
end
If these are soccer games, I'm impressed!
collegestudent
collegestudent 2020-4-6
This worked great thank you so much for getting back to me so quicky! No I wish it was soccer, it is Kobe's stats through his seasons :)
Tommy
Tommy 2020-4-6
Ah :'(
But happy to help!

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