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Undefined operand in function_handle

5 次查看（过去 30 天）
Jay
Jay 2020-4-7
关闭： MATLAB Answer Bot 2021-8-20
When I enter ' H(3) ' in the command line, the following error is shown:
Undefined operator '-' for input arguments of type 'function_handle'.
Error in
Trial_H>@(m)d1+s*(cos(gama)+sum(cos(gama+(pi/2-phi_i))))+((2*r)-omega)*sin(B_j(m))+(r-omega)*sum(sin((1:m-1)*pi-sum(B_j(1:m-1))))
Here is the code:
% Variables
L = 10;
R = 1;
r = R/(m+1);
S = sqrt(2);
s = S/(m+1);
d1 = 1;
d2 = 0.25;
omega = R/(3*(m+1));
gama = atan(R/d1);
% Functions
phi_i = @(ii, m) atan( (d1+(ii*d2)./(m+1) )./(r/3) );
B_j = @(ii, m) 2*phi_i(ii, m);
H = @(m) d1 + s*( cos(gama) + sum(cos(gama+(pi/2-phi_i(1:m)))) ) + ( (2*r)-omega)*sin(B_j(m) ) + (r-omega)*sum(sin((1:m-1)*pi - sum(B_j(1:m-1))));

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回答（1 个）

Tommy
Tommy 2020-4-7
Where you call phi_i or B_j within the definition of H, you need to supply the arguments ii and m. For example,
..(pi/2-phi_i)..
is problematic because MATLAB thinks you are trying to subtract the function phi_i from pi/2. If you pass arguments,
..(pi/2-phi_i(1,m))..
for example, MATLAB will instead subtract the output of phi_i from pi/2.
  7 个评论
显示 5更早的评论
Tommy
Tommy 2020-4-7
You cannot use m only, because your definition of B_j
B_j = @(ii, m) 2*phi_i(ii, m)
requires both ii and m.
Steven Lord
Steven Lord 2020-4-7
Calling B_j, which requires two inputs, with just one would be like me asking you "The first number is 7. What is the sum of the two numbers?" There's not enough information to answer the question.

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