Why Undefined operator '-' in function_handle?

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Jay
Jay 2020-4-7
编辑： Walter Roberson 2020-4-7
When I enter ' H(3) ' in the command line, the following error is shown:
Undefined operator '-' for input arguments of type 'function_handle'.
Error in
Trial_H>@(m)d1+s*(cos(gama)+sum(cos(gama+(pi/2-phi_i))))+((2*r)-omega)*sin(B_j(m))+(r-omega)*sum(sin((1:m-1)*pi-sum(B_j(1:m-1))))
Here is the code:
% Variables
m = 3;
L = 10;
R = 1;
r = R/(m+1);
S = sqrt(2);
s = S/(m+1);
d1 = 1;
d2 = 0.25;
omega = R/(3*(m+1));
gama = atan(R/d1);
% Functions
phi_i = @(ii, m) atan( (d1+(ii*d2)./(m+1) )./(r/3) );
B_j = @(ii, m) 2*phi_i(ii, m);
H = @(m) d1 + s*( cos(gama) + sum(cos(gama+(pi/2-phi_i))) ) + ( (2*r)-omega)*sin(B_j(m) ) + (r-omega)*sum(sin((1:m-1)*pi - sum(B_j(1:m-1))));
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Walter Roberson
Walter Roberson 2020-4-7
编辑：Walter Roberson 2020-4-7
H = @(m) d1 + s*( cos(gama) + sum(cos(gama+(pi/2-phi_i))) ) + ( (2*r)-omega)*sin(B_j(m) ) + (r-omega)*sum(sin((1:m-1)*pi - sum(B_j(1:m-1))));
^^^^^^
That is a reference to the anonymous function phi_i but it is not a call to run phi_i with particular parametrs.
B_j = @(ii, m) 2*phi_i(ii, m);
That defines B_j as being a handle to an anonymous function that expects two parameters
H = @(m) d1 + s*( cos(gama) + sum(cos(gama+(pi/2-phi_i))) ) + ( (2*r)-omega)*sin(B_j(m) ) + (r-omega)*sum(sin((1:m-1)*pi - sum(B_j(1:m-1))));
^^^^^^ ^^^^^^^^^^
Those two places, you try to invoke B_j with one parameter.
Where is the ii value coming from that you expect to pass into B_j and phi_i ?
Jay
Jay 2020-4-7
编辑：Jay 2020-4-7
I have to input a value for it. Thank you for the very explicit explanation

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