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Function like "find" but for lines

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steve Brian
steve Brian 2020-4-7
评论： steve Brian 2020-4-7
Hi everyone, I need a function that starts counting every element in an array (each line), and when it finds 0, it can skip it.
ex: A = [6 5 0 1; 3 1 0 0; 12 0 100 20]
newA = [ 1 2 4 5 6 9 11 12]
I was trying something like this:
k = 0;
colind = 1:numel(A);
colind(A!=k)
But it only takes me each column in the matrix.
wrong: newA = [1 2 3 4 5 9 10 12]
I want to count my elements on each line of the matrix. A little help please! :)

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采纳的回答

Stephen23
Stephen23 2020-4-7
>> B = find(A.').'
B =
1 2 4 5 6 9 11 12
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更多回答（2 个）

Birdman
Birdman 2020-4-7
B=reshape(A.',1,[]);
C=(1:numel(A)).*(B~=0);
C=C(C~=0)
Ameer Hamza
Ameer Hamza 2020-4-7
编辑：Ameer Hamza 2020-4-7
new_A = find(A')
  2 个评论
steve Brian
steve Brian 2020-4-7
And if i want to reset count on each line?
something like this:
A = [100 0 0 2 0; 3 4 0 5 0; 6 0 7 8 9; 0 0 10 11 0; 0 0 0 0 12]
newA= [1 4 1 2 4 1 3 4 5 3 4 5]
Ameer Hamza
Ameer Hamza 2020-4-7
编辑：Ameer Hamza 2020-4-7
The functionality of find function is the same, so
[new_A,~] = find(A');

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