How to plot binary sine function?

2020 4 8
2 个回答
回答已采纳
更新时间：2020 4 9
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0 个投票

binary sine function change its amplitude to minus after a peirod
for example) T=3, Range 0~6
y=sin(t/3) for 0<=t<3
y=-sin(t/3) for 3<=t<6
it reculsively occurs for whole range
6~9, 15~18, ....
9~12, 18~21, ....
how to plot this graph?

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 采纳的回答

Akira Agata
Akira Agata 2020-4-8

0 个投票

How about modulating a phase with 0 <-> pi ?
The following is an example:
T = 3;
time = linspace(0,T*4,1000);
% Create a phase 0 <-> pi
binary = mod(floor(time/3),2) == 1;
phi = pi*binary;
% Plot a phase modulated signal
figure
plot(time,sin(2*pi*(1/T)*time + phi))

更多回答（1 个）

David Hill
David Hill 2020-4-8

0 个投票

t=0:.01:30:
y=sin(2*pi*t/3).*(-1).^floor(t/3);%I think you are missing the 2*pi
plot(t,y);

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NoYeah
NoYeah 2020-4-8
编辑：NoYeah 2020-4-8
I did that expression before the question. but something went crazy depends on frequency and time interval. if any term of floor(blah) is containg fractional exponent, it brings whole results into complex plane and distort whole graph into something strange thing
for example) below yields complex value. not -1
(-1)^(99/10)
David Hill
David Hill 2020-4-8
It works fine for me, floor is never fractional.
NoYeah
NoYeah 2020-4-9
yes but if you set floor set fractional, the result may not correct

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