confronting cell with abelians (logic values)

1 次查看（过去 30 天）
gabriele fadanelli
评论： the cyclist 2020-4-8
I have a question about the way to extract some data from a cell based on some "indices" (in this case I want only to get as an output the "1-associated" values, e.g.:
A={'a' 'b' 'c'; 'd' 'e' 'f';'g' 'h' 'i'}
B=eye(3);
...formula to compare the arrays....
C={'a' '0' '0'; '0' 'e' '0';'0' '0' 'i'}
or
C={'a' nan nan; nan 'e' nan;nan nan 'i'}
I really cannot see the way to easily do it. Thanks

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采纳的回答

the cyclist
the cyclist 2020-4-8
Here is one way:
C = A;
C(~B) = {'0'};

更多回答（1 个）

Ameer Hamza
Ameer Hamza 2020-4-8
[A{~B}] = deal('0');
  1 个评论
the cyclist
the cyclist 2020-4-8
A simpler version of this idea is
A(~B) = {'0'}
Caution: this solution overwrites A itself, which you may not want.

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