confronting cell with abelians (logic values)
显示 更早的评论
I have a question about the way to extract some data from a cell based on some "indices" (in this case I want only to get as an output the "1-associated" values, e.g.:
A={'a' 'b' 'c'; 'd' 'e' 'f';'g' 'h' 'i'}
B=eye(3);
...formula to compare the arrays....
C={'a' '0' '0'; '0' 'e' '0';'0' '0' 'i'}
or
C={'a' nan nan; nan 'e' nan;nan nan 'i'}
I really cannot see the way to easily do it. Thanks
采纳的回答
the cyclist
2020-4-8
Here is one way:
C = A;
C(~B) = {'0'};
更多回答（1 个）
Ameer Hamza
2020-4-8
[A{~B}] = deal('0');
1 个评论
the cyclist
2020-4-8
A simpler version of this idea is
A(~B) = {'0'}
Caution: this solution overwrites A itself, which you may not want.
类别
在 帮助中心 和 File Exchange 中查找有关 Logical 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
