How to create diagonal block matrix

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raina RAJ 2020-4-9

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评论： raina RAJ 2020-4-11

I am trying to write code for the above matrix. I am very new to MATLAB programming. If anyone can help me in someway, It will be very nice. Thank you.

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Answer 1

Tommy 2020-4-9

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https://ww2.mathworks.cn/matlabcentral/answers/516532-how-to-create-diagonal-block-matrix#answer_424926

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How about this?

>> blkdiag(reshape(1:9,3,3)', [1,2;4,5], [1,2;4,5], 1, 1)
ans =
   2     3     0     0     0     0     0     0
   5     6     0     0     0     0     0     0
   8     9     0     0     0     0     0     0
   0     0     1     2     0     0     0     0
   0     0     4     5     0     0     0     0
   0     0     0     0     1     2     0     0
   0     0     0     0     4     5     0     0
   0     0     0     0     0     0     1     0
   0     0     0     0     0     0     0     1

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raina RAJ 2020-4-11

I will explain in the details the whole thing. 'c' will determine the size of blocks which I already explained to you that they will be in decreasing order. 'g' is basically used in a_t = ,min{j,c-g}. Here a_t determines how many time a block should be repeated. For example in case of c=3 and g=1, first block will be of size c+1 i.e. 4 now how many times it should be repeated??? It can be determined by a_t. Here j=1, c=3, g=1 so a_t = min{1,3-1}=1. So the first block will be repeated 1 time. Now the second block. It will have dimension 'c' as I expained earlier. Now the number of times this block will be repeated is a_t = min{2,3-1}=2 since j=2 here. So the second block will be repeated 2 times. Now the third block. Again it will have size 'c-1' and the number of times it will be repeated is a_t=min{3,3-1}=2. So the third block also will be repeated 2 times. Similarly last block will have dimension 'c-2' and it will be repeated a_t = min{4,3-1}=2 times. So the output will look like something as following:

1 1 1 1 0 0

0 0 0 0 1 1 1

0 0 0 0 0 0 0 1 1 1

0 0 0 0 0 0 0 0 0 0 1 1

0 0 0 0 0 0 0 0 0 0 0 0 1 1

0 0 0 0 0 0 0 0 0 0 0 0 0 0 1

0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1

Tommy 2020-4-11

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Thank you, that was just what I needed! Please, let me know if the following works:

c = input('c? ');
g = input('g? ');
M = cell(c+1,1);
a_t = min([1:c+1;repmat(c-g,1,c+1)]);
for i = 1:c+1
    MCell = repmat({sym([char(i-1+'A') '%d%d'], [c+2-i c+2-i])}, 1, a_t(i));
    M{i} = blkdiag(MCell{:});
end
B=blkdiag(M{:});

raina RAJ 2020-4-11

It's perfect Thank you so much

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How to create diagonal block matrix

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