I am trying to solve this ques but I am getting some trouble. Write a custom function with the declaration: PPTask1p2_f(N) and save it in a file named PPTask1p2_f.m.The function loops through the values from 1 to N and for each number n it should dis

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A M Saif Ben Kabir Amit 2020-4-9

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回答： Vinai Datta Thatiparthi 2020-4-13

Write a custom function with the declaration: PPTask1p2_f(N) and save it in a file named PPTask1p2_f.m.The function loops through the values from 1 to N and for each number n it should display in the command window: ‘n is divisible by 3’ (use disp function), ‘n is divisible by 5’, ‘n is divisible by 3 AND 5’, or ‘n is NOT divisible by 3 or 5’. You must use a for loop, the function rem to figure out if a number is divisible by 3 or 5, and num2str to convert each number to a string for displaying. You can use any combination of if, else, and elseif. Call the function in the command window: PPTask1p2_f(25) and verify if the following information is displayed: >> PPTask1p2_f(25) 1 is NOT divisible by 3 or 5 2 is NOT divisible by 3 or 5 3 is divisible by 3 4 is NOT divisible by 3 or 5 5 is divisible by 5 6 is divisible by 3 7 is NOT divisible by 3 or 5 8 is NOT divisible by 3 or 5 9 is divisible by 3 10 is divisible by 5 11 is NOT divisible by 3 or 5 12 is divisible by 3 13 is NOT divisible by 3 or 5 14 is NOT divisible by 3 or 5 15 is divisible by 3 AND 5 16 is NOT divisible by 3 or 5 17 is NOT divisible by 3 or 5 18 is divisible by 3 19 is NOT divisible by 3 or 5 20 is divisible by 5 21 is divisible by 3 22 is NOT divisible by 3 or 5 23 is NOT divisible by 3 or 5 24 is divisible by 3 25 is divisible by 5

function PPTask1p2_f(n)
for i=1:1:n
    x=rem(i,3)
   if x>=1
        disp('n is not devisable by 3 or 5')
   elseif x==0
       disp('n is  devisable by 3') 
    end
end

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matquest 2020-4-9

What trouble are you having with the function? You have only posted the homework question and a code snippet. What is your approach to solving the problem?

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Answer 1

Vinai Datta Thatiparthi 2020-4-13

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Hello,

Firstly, use the rem function to get the remainders of every value of 'i' with 3 & 5 -

r3 = rem(i,3);
r5 = rem(i,5);

Next, use if-else loops to work with different possible scenarios. Use logical operators to get desired outputs -

if ~(r3 || r5)
        disp([num2str(i),' is divisible by 3 AND 5']);
    elseif (r3 && r5)
        disp([num2str(i),' is NOT divisible by 3 or 5']);
    else
        if ~r3
            disp([num2str(i),' is divisible by 3']);
        else
            disp([num2str(i),' is divisible by 5']);
        end
    end