How to make a bode plot from a transfer function
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Hi how would I make a blode plot from this transfer function?
Gp(s) = (10e^-0.25S)/((1+1.2S)(1+3.5S))
is this the correct code in Matlab?
采纳的回答
Star Strider
2020-4-9
Yes.
The code you posted:
s = tf('s');
g = 10*exp(-0.25*s)/((1+1.2*s)*(1+3.5*s))
figure
bode(g)
grid
should work.
Are you having problems with it?
4 个评论
Uzair Akhtar
2020-4-9
Star Strider
2020-4-9
My pleasure.
You can calculate those yourself if necessary from the bode plot output:
Uzair Akhtar
2020-4-9
Thank you really appreciate your help.
Im quite new to Matlab so I just wanted to confirm if I entered this transfer function correctly in the matlab code I sent in the previous message.
Thanks again.
Star Strider
2020-4-9
As always, my pleasure!
It looks correct to me. Note that the exponential term is an output delay that primarily affects the phase of the Bode plot.
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